1.2=5t^2

Solution for 1.2=5t^2 equation:

1.2=5t^2

We move all terms to the left:

1.2-(5t^2)=0

a = -5; b = 0; c = +1.2;
Δ = b2-4ac
Δ = 02-4·(-5)·1.2
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{6}}{2*-5}=\frac{0-2\sqrt{6}}{-10}
=-\frac{2\sqrt{6}}{-10}
=-\frac{\sqrt{6}}{-5}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{6}}{2*-5}=\frac{0+2\sqrt{6}}{-10}
=\frac{2\sqrt{6}}{-10}
=\frac{\sqrt{6}}{-5}
$